2/5x^2+1/5x-2=0

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Solution for 2/5x^2+1/5x-2=0 equation: 


x in (-oo:+oo)

(2/5)*x^2+(1/5)*x-2 = 0

2/5*x^2+1/5*x-2 = 0

DELTA = (1/5)^2-(-2*2/5*4)

DELTA = 81/25

DELTA > 0

x = ((81/25)^(1/2)-1/5)/(2/5*2) or x = (-(81/25)^(1/2)-1/5)/(2/5*2)

x = 2 or x = -5/2

x in { -5/2, 2 }

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